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If the motor exerts a force of [tex]f = (600 + 2s^2) \, \text{N}[/tex] on the cable, determine the speed of the 122-kg crate when it rises to [tex]s = 15 \, \text{m}[/tex]. The crate is initially at rest on the ground.

Answer :

To find the speed of the 122 kg crate when it rises to s = 15 m, given that the motor exerts a force of F = (600 2s²) N on the cable, we need to apply the following steps:Given data

:Mass of the crate, m = 122 kg

Initial velocity of the crate, u = 0 m/s

Height to which the crate is lifted, s = 15 m

Force exerted by the motor,

F = (600 2s²) N

We can use the work-energy theorem to find the velocity of the crate when it reaches the height of 15 m. The work-energy theorem states that the net work done on an object is equal to the change in its kinetic energy.

Let's substitute the given values in the above equation:

W = (600 2s²) × 15= 18000s² J

We know that the net work done on the crate is equal to the change in its kinetic energy. When the crate is lifted to the height of 15 m, its kinetic energy changes from zero to some final value.

learn more about kinetic energy

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