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A constant applied force of 43.6 N lifts a 3.42 kg mass straight up. If the object's change in gravitational potential energy is 118 J, what is the object's change in kinetic energy?

Answer :

The object's change in kinetic energy is approximately 90.69 J.

To determine the object's change in kinetic energy, we need to use the conservation of energy principle. According to this principle, the change in gravitational potential energy (GPE) of the object is equal to the negative of the change in kinetic energy (KE). In other words: ΔGPE = -ΔKE

Given that the object's change in gravitational potential energy (ΔGPE) is 118 J, we can set up the equation as follows:
118 J = -ΔKE

Since the object is being lifted straight up, the work done by the applied force is equal to the change in gravitational potential energy. The work done (W) can be calculated using the formula: W = Fd

where F is the applied force and d is the distance traveled. In this case, the distance traveled is the height the object is lifted.

Let's calculate the height by rearranging the equation for work: W = Fd
118 J = (43.6 N)(d)
Solving for d:
d = 118 J / 43.6 N
d ≈ 2.706 m

Now that we know the height, we can calculate the change in kinetic energy using the equation: ΔKE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height.

Given that the mass (m) is 3.42 kg, and the acceleration due to gravity (g) is approximately 9.8 m/s², we can substitute these values into the equation:

ΔKE = (3.42 kg)(9.8 m/s²)(2.706 m)

Calculating:

ΔKE ≈ 90.69 J

Therefore, the object's change in kinetic energy is approximately 90.69 J.

Learn more about kinetic energy from the given link

https://brainly.com/question/8101588

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