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A 65-kg hiker climbs to the top of a 3700 m high mountain. The climb is made in 5.0 hours, starting at an elevation of 2300 m. Calculate the work done by the hiker against gravity.

Answer :

Final answer:

The work done by a 65-kg hiker climbing to the top of a 3700m high mountain (starting from an elevation of 2300m) against gravity is 889,000 Joules.

Explanation:

To calculate the work done by the hiker against gravity, we need to use the formula for work against the gravitational force, which is Work (W) = mass (m) × gravity (g) × height change (Δh).

The mass of the hiker is 65 kg, the acceleration due to gravity is approximately 9.8 m/s2, and the change in height is the difference between the final elevation and the starting elevation, which is 3700 m - 2300 m = 1400 m.

The work done by the hiker can be calculated as follows:

  • W = m × g × Δh
  • W = 65 kg × 9.8 m/s2 × 1400 m
  • W = 65 × 9.8 × 1400
  • W = 889,000 Joules

Therefore, the work done by the hiker against gravity is 889,000 Joules.

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