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A 1.4 m string, fixed at both ends, resonates at 210 Hz, 240 Hz, 270 Hz, and 300 Hz between 200 and 300 Hz.

1. What is the fundamental frequency, [tex]f[/tex], for this string?
2. What is the wavelength, [tex]\lambda[/tex], on the string at 210 Hz?
3. What is the speed of the waves, [tex]v[/tex], on the string?

Answer :

Final Answer:

1. Fundamental frequency (f)= 150 Hz

2. Wavelength (λ) at 210 Hz= 0.64 m

3. Wave speed (v) on the string= 96 m/s

Explanation:

The fundamental frequency (first harmonic) of the string is calculated by taking the average of the given resonant frequencies (210 Hz, 240 Hz, 270 Hz, and 300 Hz). Thus, [tex]\( f = \frac{210 + 240 + 270 + 300}{4} = 150 \)Hz[/tex].

To find the wavelength (λ) at 210 Hz, we can use the formula

[tex]\( f = \frac{v}{λ} \)[/tex], rearranged to [tex]\( λ = \frac{v}{f} \)[/tex] ,given that f- 210Hz and we already know the wave speed (v) on the string is constant, we can calculate

[tex]\( λ = \frac{96}{210} \approx 0.64 \) m[/tex].

The wave speed (v) on the string can be determined by the formula

[tex]\( v = f \times λ \)[/tex]. Using the fundamental frequency (f = 150 Hz) and the wavelength (λ) calculated at 210 Hz, we get [tex]\( v = 150 \times 0.64 \approx 96 \) m/s[/tex].

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