High School

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Which equation, when solved, results in a different value of [tex]x[/tex] than the other three?

A. [tex]8.3 = -0.6x + 11.3[/tex]
B. [tex]11.3 = 8.3 + 0.6x[/tex]
C. [tex]11.3 - 0.6x = 8.3[/tex]
D. [tex]8.3 - 0.6x = 11.3[/tex]

Answer :

Answer: The correct equation is (D) [tex]8.3-0.6x=11.3.[/tex]

Step-by-step explanation: We are to select the equation that results in a different value of 'x' than the other three equations.

Let us solve the equations one by one.

(A). We have

[tex]8.3=-0.6x+11.3\\\\\Rightarrow -0.6x=8.3-11.3\\\\\Rightarrow -0.6x=-3\\\\\Rightarrow x=\dfrac{3}{0.6}\\\\\Rightarrow x=5.[/tex]

(B) We have

[tex]11.3=8.3+0.6x\\\\\Rightarrow 0.6x=11.3-8.3\\\\\Rightarrow 0.6x=3\\\\\Rightarrow x=\dfrac{3}{0.6}\\\\\Rightarrow x=5.[/tex]

(C) We have

[tex]11.3-0.6x=8.3\\\\\Rightarrow 0.6x=11.3-8.3\\\\\Rightarrow 0.6x=3\\\\\Rightarrow x=\dfrac{3}{0.6}\\\\\Rightarrow x=5.[/tex]

(D) We have

[tex]8.3-0.6x=11.3\\\\\Rightarrow -0.6x=11.3-8.3\\\\\Rightarrow -0.6x=3\\\\\Rightarrow x=-\dfrac{3}{0.6}\\\\\Rightarrow x=-5.[/tex]

Therefore, we see that the solution of the first three equations is x = 5 and the solution of the last equation is x = - 5.

Thus, the equation (D) results in a different value of 'x' when solved.Option (D) is correct.

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Rewritten by : Barada

solve each one to find that D is the answer