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Answer :
The energy stored in the inductor is 1.125 Joules at a steady state.
When an inductor reaches its steady-state current, the energy stored in the inductor can be calculated using the formula:
- E = (1/2) × L × I², where L is the inductance and I is the current.
The steady-state current (I) can be calculated as the emf (V) divided by the resistance (R):
- I = V / R = 6.00 V / 8.00 Ω = 0.75 A
Now, substituting the values into the energy formula:
- E = (1/2) × 4.00 H × (0.75 A)² = (1/2) × 4.00 H × 0.5625 A² = 1.125 J
Therefore, the energy stored in the inductor is 1.125 Joules.
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