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Answer :
The amount of energy a 69.7 kg object will have if it is moving at 30.3 ms⁻¹ is 31,293.52 joules. The amount of energy a 48.9 kg object will have if it is moving at 36.3 m s⁻¹ is 7,563.44 calories.
The kinetic energy of an object in motion can be calculated using the formula K.E= (1/2)mv², where m is the mass of the object and v is its velocity. We can use this formula to calculate the kinetic energy of the given objects.
To calculate the kinetic energy of a 69.7 kg object moving at 30.3 ms⁻¹, we can use the formula K.E= (1/2)mv²
K.E= (1/2) × 69.7 kg × (30.3 ms⁻¹)²
K.E= 31,293.52 J
Therefore, the 69.7 kg object has 31,293.52 joules of energy.
To calculate the kinetic energy of a 48.9 kg object moving at 36.3 ms⁻¹, we can use the formula K.E= (1/2)mv²
K.E= (1/2) × 48.9 kg × (36.3 ms⁻¹)²
K.E= 31,644.71 J
We can convert this to calories by using the conversion factor 1 cal = 4.184 J. Therefore, the kinetic energy of the 48.9 kg object is
K.E= 31,644.71 J × (1 cal/4.184 J)
K.E= 7,563.44 cal
Therefore, the 48.9 kg object has 7,563.44 calories of energy.
Learn more about kinetic energy here: https://brainly.com/question/30337295
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