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Answer :
Final answer:
The heat lost by the silver fork is calculated using the mass of the fork, the specific heat capacity of silver, and the change in temperature. The calculation shows that the fork loses 352.5 joules of heat as it cools.
Explanation:
The student is asking how much heat is lost by a 0.03 kg silver fork when it cools from 373.15 K to 323.15 K. The specific heat capacity of silver is given as 235 J/kg·K. To find the heat lost, the following heat transfer equation can be used:
Q = mcΔT
Where:
- Q is the heat lost,
- m is the mass of the fork,
- c is the specific heat capacity of silver, and
- ΔT is the change in temperature.
Plugging in the given values:
Q = (0.03 kg) × (235 J/kg·K) × (373.15 K - 323.15 K)
Q = (0.03 kg) × (235 J/kg·K) × (50 K)
Q = (0.03 kg) × (11,750 J/kg)
Q = 352.5 J
Therefore, the silver fork loses 352.5 joules of heat as it cools down.
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