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Answer :
Answer:
7,55 seg
Step-by-step explanation:
Initial Velocity = 60 ft/s
High = 3ft
Acceleration = -16 ft/s2
According to the next formula
H = Vi(t) - 1/2 gt2
We got a cuadratic formula which roots are
t1 = -0,04 seg and t2 = 7,55 seg
the time not negative so t= 7,55 seg
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Answer:
Answer:
t = 3.8 s
option 3
Step-by-step explanation:
For this case we have the following equation:
h (t) = at ^ 2 + v * t + h0
Substituting values we have:
h (t) = - 16 * t ^ 2 + 60 * t + 3
We equate the equation to zero:
-16 * t ^ 2 + 60 * t + 3 = 0
We look for the roots of the polynomial:
t1 = -0.04935053979258153
t2 = 3.7993505397925817
We are left with the positive root and round:
t2 = 3.8 s