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Answer :
The value of ΔE for a system that performs 190 kJ of work on its surroundings and gains 250 kJ of heat is 60 kJ. Option C.
ΔE stands for the difference between the energy of a system before and after a reaction. As a result, the value of ΔE for a system that performs 190 kJ of work on its surroundings and gains 250 kJ of heat can be calculated as follows:
ΔE = q + w where, q = heat supplied (250 kJ)w = work done (-190 kJ)
Therefore,ΔE = 250 kJ + (-190 kJ)ΔE = 60 kJ
The value of ΔE is 60 kJ when a system that performs 190 kJ of work on its surroundings and gains 250 kJ of heat. Option C.
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