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Answer :
The percent yield of producing calcium hydroxide from the reaction is 69.5%.
Identify the balanced equation: CaO + H₂O → Ca(OH)₂
Calculate the moles of CaO reacted:
Molar mass of CaO = 56.08 g/mol
Moles of CaO = 37.6 g / 56.08 g/mol
= 0.670 moles
Determine the theoretical yield of Ca(OH)₂:
Molar mass of Ca(OH)₂ = 74.10 g/mol
The moles of CaO reacted will produce an equal amount of Ca(OH)₂ due to the 1:1 stoichiometry.
Mass of Ca(OH)₂ = 0.670 moles × 74.10 g/mol
= 49.64 g
Calculate the percent yield:
Percent yield = (Actual yield / Theoretical yield) × 100
Percent yield = (34.5 g / 49.64 g) × 100
≈ 69.5%
So, the percent yield of producing calcium hydroxide is 69.5%.
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