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Answer :
Final answer:
The 36.3-gram sample of pure gold would displace approximately 1.88 mL of water.
Explanation:
To find the volume of water displaced by a 36.3-gram sample of pure gold, we need to use the fact that density is the mass-to-volume ratio. For gold, the density is 19.3 g/mL. Therefore, we can determine the volume of gold by dividing the mass by the density:
Volume of gold = Mass / Density
Volume of gold = 36.3 g / 19.3 g/mL
Volume of gold ≈ 1.88 mL
Therefore, the 36.3-gram sample of pure gold would displace approximately 1.88 mL of water.
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