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Calculate the gravitational field at the pendulum’s location.

A pendulum with a length of 36.9 cm has a period of 1.22 s.

Answer :

The gravitational field at the pendulum's location, calculated using the formula for the period of a simple pendulum, is approximately [tex]9.82 m/s^2.[/tex]

To calculate the gravitational field at the pendulum's location, we can use the formula for the period of a simple pendulum, which is given by:

[tex]T = 2\pi \sqrt{} (L/g)[/tex]

Here, T is the period, L is the length of the pendulum, and g is the gravitational field (or acceleration due to gravity). The goal is to solve for g, so we rearrange the formula to:

[tex]g = (4\pi ^2 * L) / T^2[/tex]

Substituting the given values into the equation:

L = 36.9 cm = 0.369 m (since g is typically in m/s² we convert length to meters)

T = 1.22 s

[tex]g = (4\pi ^2 * 0.369 ) / (1.22 s)^2[/tex]

After performing the calculation:

g = [tex]9.82 m/s^2.[/tex]

Therefore, the acceleration due to gravity at the location of the pendulum is approximately [tex]9.82 m/s^2.[/tex]

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Rewritten by : Barada

From the calculation, the gravitational field at the pendulum’s location is 9.8 m/s^2

What is a pendulum?

A pendulum is a device that is used to demonstrate oscillatory motion. We have the following information.

l = 36.9 cm or 0.369 m

T = 1.22 s

Then;

T = 2π√l/g

T/2π = √l/g

(T/2π)^2 = l/g

g(T/2π)^2 = l

g = l/(T/2π)^2

g = 0.369/(1.22/2 *3.14)^2

g = 9.8 m/s^2

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