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Answer :
Therefore, the volume of the weather balloon at 295 K and 106.4 atm is approximately 99.2 L. To solve this problem, we need to use the combined gas law, which states that the product of pressure and volume is proportional to the absolute temperature.
Mathematically, this can be expressed as:
P1V1/T1 = P2V2/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature.
In this case, we have:
P1 = 98.3 atm
V1 = 105 L
T1 = 300 K
P2 = 106.4 atm
T2 = 295 K
We want to find V2.
First, we need to convert the temperatures to absolute temperature units (kelvin):
T1 = 300 K
T2 = 295 K
Now we can plug in the values and solve for V2:
(98.3 atm)(105 L)/(300 K) = (106.4 atm)(V2)/(295 K)
Simplifying and solving for V2, we get:
V2 = (98.3 atm)(105 L)(295 K)/(106.4 atm)(300 K) = 99.2 L
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