High School

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A former student of mechanics wishes to weigh himself but has access only to:

a. A scale with a capacity limited to 120 lbs.
b. A small 20-lb spring dynamometer.

With the rig shown, he discovers that when he exerts a pull on the rope so that the dynamometer registers 17 lbs, the scale reads 94 lbs.

What is his correct weight?

Answer :

Final answer:

The correct weight of the former student can be found by adding the scale reading and the dynamometer reading. His correct weight is 111 lb.

Explanation:

To solve this problem, we need to add the reads of the scale (94 lb) and the spring dynamometer (17 lb). Since the dynamometer is measuring the force that is being exerted by the person's pull on the rope, it is reducing the force being exerted on the scale, and thus reducing its reading from the actual weight. Therefore, to get the actual weight, we have to add the weight reading of the scale and that of the dynamometer.

So, the man's correct weight is 94 lb + 17 lb = 111 lb.

Learn more about Weight Calculation here:

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