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Answer :
To find the potential energy of a 25 kg bicycle at the top of a 3 m high hill, we can use the formula for potential energy:
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height (in meters).
Let's fill in the values:
- [tex]\( m = 25 \, \text{kg} \)[/tex]
- [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- [tex]\( h = 3 \, \text{m} \)[/tex]
Now, substitute these values into the formula:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
Calculating this gives:
[tex]\[ PE = 25 \times 9.8 = 245 \][/tex]
[tex]\[ PE = 245 \times 3 = 735 \][/tex]
So, the potential energy of the bicycle is 735 Joules.
The correct answer is 735 J.
[tex]\[ PE = m \times g \times h \][/tex]
where:
- [tex]\( m \)[/tex] is the mass (in kilograms),
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth),
- [tex]\( h \)[/tex] is the height (in meters).
Let's fill in the values:
- [tex]\( m = 25 \, \text{kg} \)[/tex]
- [tex]\( g = 9.8 \, \text{m/s}^2 \)[/tex]
- [tex]\( h = 3 \, \text{m} \)[/tex]
Now, substitute these values into the formula:
[tex]\[ PE = 25 \times 9.8 \times 3 \][/tex]
Calculating this gives:
[tex]\[ PE = 25 \times 9.8 = 245 \][/tex]
[tex]\[ PE = 245 \times 3 = 735 \][/tex]
So, the potential energy of the bicycle is 735 Joules.
The correct answer is 735 J.
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