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The solubility of a compound is 33.1 g/100 mL at 25°C and 37.1 g/100 mL at 108°C. If a saturated solution at 108°C cools to 25°C, what is the expected outcome?

A. Decrease in solubility
B. Increase in solubility
C. Solubility remains constant
D. Precipitation occurs

Answer :

Final answer:

The solubility of a compound decreases as temperature decreases, leading to precipitation as the solution cools from 108°C to 25°C, hence correct answer is D. Precipitation occurs.

Explanation:

Solubility and Temperature: The solubility of most solids increases with increasing temperature. This means a hot solution can hold more dissolved solute than a cold solution.

Saturated Solution: A saturated solution is one that contains the maximum amount of solute that can dissolve at a given temperature. If you try to add more solute, it will precipitate (form a solid) because the solution is already at its maximum capacity.

In this scenario: We have a saturated solution at 108°C, which means it contains 37.1 g of the compound dissolved in 100 mL of solution.

When this solution cools to 25°C, the solubility of the compound decreases to 33.1 g per 100 mL.

Since the solution originally contained 37.1 g (more than the saturation limit at 25°C), the excess solute (37.1 g - 33.1 g = 4 g) will come out of solution and form a precipitate.

Therefore, cooling the saturated solution from 108°C to 25°C will result in precipitation.

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