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1SG Smith, mentioned in the previous question, has a height of 5 feet 4 inches and average circumference measurements of 13 inches for the neck, 32 inches for the waist, and 42 inches for the hips. What is her percent body fat?

Answer :

1SG Smith's body fat percentage is approximately 10.1% based on measurements of height, neck, waist, and hips using the U.S.

1. The formula is as follows:

  • Body fat percentage = 163.205 * log10(waist + hip - neck) - 97.684 * log10(height) - 104.912.

2. Using the given measurements:

  • Height in inches = 64 inches
  • Neck = 13 inches
  • Waist = 32 inches
  • Hips = 42 inches
  • Waist + hip - neck = 32 + 42 - 13 = 61 inches

3. Applying these values to the formula:

  • Body fat percentage = 163.205 * log10(61) - 97.684 * log10(64) - 104.912
  • = 163.205 * 1.785 - 97.684 * 1.806 - 104.912
  • = 291.414 - 176.409 - 104.912
  • = 10.093

Thus, 1SG Smith's body fat percentage is approximately 10.1%.

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