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30ml of 0.6M sodium acetate solution is added to 50ml of 2M of

acetic acid to form a buffer . What is the total concentration of

the buffer.

[total buffer] = [buffer acid] + [buffer base]

Answer :

The total concentration of the buffer which was formed after the addition of 30 mL of 0.6M sodium acetate solution to 50 mL of 2M acetic acid solution can be determined as follows:

In order to calculate the total buffer concentration, we will need to find the concentration of the buffer acid and buffer base. Buffer acid is the acetic acid used to form the buffer and Buffer base is sodium acetate used to form the buffer.

Buffer Acid Concentration:

Volume of acetic acid solution = 50 mL = 0.050L

Concentration of acetic acid = 2M

Therefore, the number of moles of acetic acid in the solution = Concentration × Volume= 2M × 0.050 L= 0.10 moles

Molar mass of acetic acid = 60.05 g/mol

Mass of acetic acid in the solution = Number of moles × Molar mass= 0.10 mol × 60.05 g/mol= 6.005 g

Buffer Base Concentration:

Volume of sodium acetate solution = 30 mL = 0.030L

Concentration of sodium acetate = 0.6M

Therefore, the number of moles of sodium acetate in the solution

= Concentration × Volume= 0.6M × 0.030 L= 0.018 moles

Molar mass of sodium acetate = 82.03 g/mol

Mass of sodium acetate in the solution = Number of moles × Molar mass

= 0.018 mol × 82.03 g/mol

= 1.47654 g

Total Buffer Concentration:

The total concentration of buffer

= [buffer acid] + [buffer base]= (mass of acetic acid in the solution / molar mass of acetic acid) + (mass of sodium acetate in the solution / molar mass of sodium acetate)

= (6.005 / 60.05) + (1.47654 / 82.03)= 0.0999 + 0.018 = 0.1179 moles/L (total buffer)

Therefore, the total concentration of buffer is 0.1179 moles/L.

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