Answer :

To write the abbreviated electron configuration for the As[tex]^{3+}[/tex] ion, we need to follow these steps:


  1. Identify the Element and its Atomic Number:
    Arsenic (As) is the element in question. Its atomic number is 33, meaning it has 33 electrons in its neutral state.


  2. Write the Electron Configuration for Neutral Arsenic:
    The electron configuration for a neutral arsenic atom is:
    [tex]1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^6 \, 4s^2 \, 3d^{10} \, 4p^3[/tex]
    In its abbreviated form, using the previous noble gas (Krypton, Kr), it would be:
    [tex][Ar] \, 3d^{10} \, 4s^2 \, 4p^3[/tex]


  3. Determine the Electron Configuration for the As[tex]^{3+}[/tex] Ion:
    When As loses three electrons to become As[tex]^{3+}[/tex], these electrons are typically removed from the outermost shell; the order is generally from the highest energy level present. Thus:
    [tex][Ar] \, 3d^{10} \, 4s^2[/tex]
    This is achieved by removing the three 4p electrons.


  4. Abbreviated Electron Configuration of As[tex]^{3+}[/tex]:
    The abbreviated electron configuration for As[tex]^{3+}[/tex] is:
    [tex][Ar] \, 3d^{10} \, 4s^2[/tex]



This configuration reflects the loss of the three outermost electrons, effectively reducing the electron count and representing the ionized state of arsenic.

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Rewritten by : Barada