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A fish tank with a rectangular base has a volume of 3360 cubic inches. The length of the tank is 14 inches, the width is 12 inches, and the height is 20 inches. If one fluid ounce is 1.8 cubic inches, how much water will the tank hold? Your answer should be in gallons.

Answer :

water the tank will hold = 14.583 gallons

What is cuboid ?

  • A cuboid is a three-dimensional or solid shape.
  • A cuboid is a convex polyhedron that has six rectangular faces, eight vertices, and twelve edges.
  • Another name for a cuboid is a rectangular prism. A cube is a cuboid with six square faces.
  • The basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

Given : A fish tank has a volume = 3360 cubic Inches.

The length of the tank is =14 inches

the width is = 12 inches.

The height of the tank is = 20 inches.

If one fluid ounce is = 1.8 cubic inches

Volume of tank = 14 * 12 * 20 = 3360 cubic inches

1.8 cubic inches = one fluid ounce

3360 cubic inches = 3360/1.8 fluid ounce

= 5600/3 fluid ounce

As we know,

1 gallons = 128 fluid ounces

water the tank will hold =( 5600/3 ) / 128

= 175 / 1 = 14.583 gallons

Therefore, water the tank will hold = 14.583 gallons

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Rewritten by : Barada

Answer:

14.58 gallons

Step-by-step explanation:

The tank volume is 3360 in^3, which is the product of the base x length x height (14)(12)(29) = 3360 in^3.

We are given a conversion factor: 1 fluid oz = 1.8 in^3

We can write this as (1 fluid oz)/( 1.8 in^3).

Use this conversion factor to confert volume to fluid oz:

(3360 in^3)*((1 fluid oz)/( 1.8 in^3)) = 1867 fluid oz

There are 128 fluid oz/gallon. Make this into a conversion factor:

(1 gallon/128 fluid oz) [The conversion factor can be written with oz or gallon on the top - it makes no difference since the two values are equal to each other]

(1867 fluid oz)*((1 gallon/128 fluid oz) = 14.58 gallons