Answer :

Final answer:

To find the volume needed to dilute 11.8 M HNO3 to 386.2 mL of 0.18 M HNO3, we use the formula M1V1 = M2V2, yielding approximately 5.9 mL. However, this answer does not match the provided options, suggesting a potential error or need for clarification in the question or the answer choices.

Explanation:

To determine how many milliliters of 11.8 M HNO3 are needed to prepare 386.2 mL of 0.18 M HNO3, we can use the dilution formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution, and M2 and V2 are the molarity and volume of the diluted solution.

We know:

  • M1 = 11.8 M
  • M2 = 0.18 M
  • V2 = 386.2 mL

We need to find V1. So, we can rearrange the formula to solve for V1:

V1 = (M2 x V2) / M1

V1 = (0.18 M x 386.2 mL) / 11.8 M

V1 = 5.916 måö¤/¡9ö¡å¤¡¥/'ωL måö¤/¡9ö¡å¤¡¥/'ωL

After calculating this, we find that:

V1 ≈ 5.9 mL

However, none of the listed options (A, B, C, D) closely match this result. Thus, it's possible that there may have been an error in the question, in the provided options, or in the calculation if interpreting the question literally. If this was a conceptual question and the options provided are the only ones to choose from, it could suggest that additional context or clarification is needed to select the correct response from the choices given.

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