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Answer :
To solve the division problem [tex]\(7 \longdiv 181\)[/tex], we need to find how many times 7 goes into 181 and what the remainder is.
1. Determine the Quotient:
- First, we divide 181 by 7.
- 7 goes into 18 two times, giving us [tex]\(7 \times 2 = 14\)[/tex].
- Subtract 14 from 18 to get a remainder of 4.
- Bring down the next digit, 1, making it 41.
- 7 goes into 41 five times, giving us [tex]\(7 \times 5 = 35\)[/tex].
- Subtract 35 from 41 to get a remainder of 6.
- Thus, the quotient is 25.
2. Determine the Remainder:
- After subtracting 35 from 41, we have a remainder of 6.
- This remainder is the part of 181 that cannot be evenly divided by 7.
3. Calculate the Decimal Result:
- To express the result as a decimal, we divide the full number 181 by 7.
- The result of this division is approximately 25.857142857142858.
In summary:
- The quotient is 25.
- The remainder is 6.
- As a decimal, [tex]\( \frac{181}{7} \approx 25.857142857142858 \)[/tex].
1. Determine the Quotient:
- First, we divide 181 by 7.
- 7 goes into 18 two times, giving us [tex]\(7 \times 2 = 14\)[/tex].
- Subtract 14 from 18 to get a remainder of 4.
- Bring down the next digit, 1, making it 41.
- 7 goes into 41 five times, giving us [tex]\(7 \times 5 = 35\)[/tex].
- Subtract 35 from 41 to get a remainder of 6.
- Thus, the quotient is 25.
2. Determine the Remainder:
- After subtracting 35 from 41, we have a remainder of 6.
- This remainder is the part of 181 that cannot be evenly divided by 7.
3. Calculate the Decimal Result:
- To express the result as a decimal, we divide the full number 181 by 7.
- The result of this division is approximately 25.857142857142858.
In summary:
- The quotient is 25.
- The remainder is 6.
- As a decimal, [tex]\( \frac{181}{7} \approx 25.857142857142858 \)[/tex].
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