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Answer :
The equilibrium temperature of the two objects will be 45.6 °C.
To find the equilibrium temperature, we need to use the principle of conservation of energy. The heat gained by the aluminum object is equal to the heat lost by the copper object.
The formula for heat transfer is Q = m c Δ T, where m is mass, c is specific heat, and ΔT is change in temperature.
Let T-f be the final temperature of both objects.
For the aluminum object:
Q = m c Δ T
Q = (2.45 kg)(900 J/kg°C)(T-f - 26.1 °C)
For the copper object:
Q = mcΔT
Q = (9.89 kg)(387 J/kg°C)(26.1 °C - T-f)
Setting the two quantities equal to each other and solving for T-f:
(2.45 kg)(900 J/kg°C)(T-f - 26.1 °C) = (9.89 kg)(387 J/kg°C)(26.1 °C - T-f)
T-f = (9.89 kg)(387 J/kg°C)(26.1 °C) / [(2.45 kg)(900 J/kg°C) + (9.89 kg)(387 J/kg°C)] + 26.1 °C
T-f = 45.6 °C
Therefore, the equilibrium temperature of the two objects is 45.6 °C.
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