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Answer:
Option (D)
Step-by-step explanation:
Standard equation of a quadratic function is,
ax² + bx + c
Comparing this function with the given quadratic function,
f(x) = 2x² - 4x - 3
a = 2, b = -4 and c = -3
By using quadratic formula to get the value of x,
x = [tex]\frac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
= [tex]\frac{-(-4)\pm \sqrt{(-4)^2-4(2)(-3)} }{2(2)}[/tex]
= [tex]\frac{4\pm\sqrt{16+24}}{4}[/tex]
= [tex]\frac{-4\pm \sqrt{40}}{4}[/tex]
= [tex]\frac{-2\pm \sqrt{10}}{2}[/tex]
Therefore, Susie made a mistake in step IV.
Option (D) is the answer.
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Rewritten by : Barada
