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Answer :
To solve the multiplication problem [tex]\(199 \cdot 181\)[/tex], we follow these steps:
1. Break Down the Multiplication:
- Multiply 199 by each digit in 181, starting from the rightmost digit.
2. Multiply by 1 (the units place in 181):
- [tex]\(199 \times 1 = 199\)[/tex].
3. Multiply by 8 (the tens place in 181):
- [tex]\(199 \times 8 = 1592\)[/tex].
- Since 8 is in the tens place, we add a zero to the right: [tex]\(15920\)[/tex].
4. Multiply by 1 (the hundreds place in 181):
- [tex]\(199 \times 1 = 199\)[/tex].
- Since 1 is in the hundreds place, we add two zeros to the right: [tex]\(19900\)[/tex].
5. Add All the Results Together:
- Now, sum up all the products:
[tex]\[
\begin{align*}
&199 \\
+&15920 \\
+&19900 \\
\end{align*}
\][/tex]
- Add them:
[tex]\[
199 + 15920 + 19900 = 36019
\][/tex]
Therefore, the result of [tex]\(199 \cdot 181\)[/tex] is [tex]\(36,019\)[/tex]. This breakdown shows each step of the multiplication process, leading to the final result.
1. Break Down the Multiplication:
- Multiply 199 by each digit in 181, starting from the rightmost digit.
2. Multiply by 1 (the units place in 181):
- [tex]\(199 \times 1 = 199\)[/tex].
3. Multiply by 8 (the tens place in 181):
- [tex]\(199 \times 8 = 1592\)[/tex].
- Since 8 is in the tens place, we add a zero to the right: [tex]\(15920\)[/tex].
4. Multiply by 1 (the hundreds place in 181):
- [tex]\(199 \times 1 = 199\)[/tex].
- Since 1 is in the hundreds place, we add two zeros to the right: [tex]\(19900\)[/tex].
5. Add All the Results Together:
- Now, sum up all the products:
[tex]\[
\begin{align*}
&199 \\
+&15920 \\
+&19900 \\
\end{align*}
\][/tex]
- Add them:
[tex]\[
199 + 15920 + 19900 = 36019
\][/tex]
Therefore, the result of [tex]\(199 \cdot 181\)[/tex] is [tex]\(36,019\)[/tex]. This breakdown shows each step of the multiplication process, leading to the final result.
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