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A 147-Newton horizontal force is exerted upon a 3.1 kg box to move it across a level surface at a constant velocity of 1.4 m/s. What is the force of friction encountered by the box?

A. 47 N
B. 105 N
C. 4.84 N
D. 147 N

Answer :

Answer:

147N

Explanation:

For an abject moving at constant velocity or at rest, the net force equals 0. Therefore, since there is a 147N force exerted forward, there must also be a 147N friction force dragging it.

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