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Answer :
To determine the density of the solid magnesium flare, follow these steps:
1. Identify the given values:
- Mass of the magnesium flare (m): 1300 grams
- Volume of the magnesium flare (V): 3 cubic meters
2. Recall the formula for density (ρ):
[tex]\[
\rho = \frac{m}{V}
\][/tex]
Where:
- [tex]\( \rho \)[/tex] (rho) is the density,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( V \)[/tex] is the volume.
3. Substitute the given values into the formula:
[tex]\[
\rho = \frac{1300 \text{ grams}}{3 \text{ cubic meters}}
\][/tex]
4. Perform the division to find the density:
[tex]\[
\rho = \frac{1300}{3}
\][/tex]
5. Divide 1300 by 3:
[tex]\[
\rho \approx 433.333 \text{ grams per cubic meter}
\][/tex]
Therefore, the density of the magnesium flare is approximately [tex]\( 433.333 \text{ grams per cubic meter} \)[/tex].
1. Identify the given values:
- Mass of the magnesium flare (m): 1300 grams
- Volume of the magnesium flare (V): 3 cubic meters
2. Recall the formula for density (ρ):
[tex]\[
\rho = \frac{m}{V}
\][/tex]
Where:
- [tex]\( \rho \)[/tex] (rho) is the density,
- [tex]\( m \)[/tex] is the mass,
- [tex]\( V \)[/tex] is the volume.
3. Substitute the given values into the formula:
[tex]\[
\rho = \frac{1300 \text{ grams}}{3 \text{ cubic meters}}
\][/tex]
4. Perform the division to find the density:
[tex]\[
\rho = \frac{1300}{3}
\][/tex]
5. Divide 1300 by 3:
[tex]\[
\rho \approx 433.333 \text{ grams per cubic meter}
\][/tex]
Therefore, the density of the magnesium flare is approximately [tex]\( 433.333 \text{ grams per cubic meter} \)[/tex].
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