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How many MJ of energy are produced when 2.28 kg of octane (C₈H₁₈; MW = 114 amu) is burned in the presence of 6.40 kg of oxygen? (ΔH = −5.00 MJ/mol C₈H₁₈)

Answer :

Final answer:

When 2.28 kg of octane is combusted with 6.40 kg of oxygen, 100 MJ of energy is produced, calculated by determining the moles of octane and applying the given enthalpy change.

Explanation:

The question asks how many megajoules (MJ) of energy are produced when 2.28 kg of octane (C8H18) is burned in the presence of 6.40 kg oxygen, given that the enthalpy change (ΔH) of combustion is −5.00 MJ/mol of C8H18.

First, we determine how many moles of octane are in 2.28 kg. Since the molecular weight (MW) of octane is 114 amu (or g/mol), we convert the mass of octane to moles:

  • Mass of octane = 2.28 kg = 2280 g
  • Moles of octane = mass / MW = 2280 g / 114 g/mol = 20 moles

Assuming complete combustion, the enthalpy change given is for 1 mole of octane. Therefore, for 20 moles:

  • Energy produced = 20 moles × (−5.00 MJ/mol) = −500 MJ = 100 MJ

Thus, when 2.28 kg of octane is combusted with 6.40 kg of oxygen, 100 MJ of energy is produced.

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