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How many moles of [tex]Al_2(SO_4)_3[/tex] are there in 100.8 g of [tex]Al_2(SO_4)_3[/tex]?

Molar mass of [tex]Al_2(SO_4)_3[/tex] = 342 g/mol.

Answer :

Final answer:

To calculate the number of moles in 100.8g of Al₂(SO₄)₃, divide the given mass by its molar mass. With a molar mass of Al₂(SO₄)₃ being 342g/mol, the formula provides an answer of approximately 0.294 moles of Al₂(SO₄)₃.

Explanation:

The concept required to solve this question involves understanding of moles and molar mass, essentials in chemistry. Given the molar mass of Al₂(SO₄)₃ is 342g/mol, we need to calculate how many moles of Al₂(SO₄)₃ we have in 100.8g of it.

To find out this, we use the formula: number of moles = mass / molar mass. Here, the mass (weight) of Al₂(SO₄)₃ is 100.8g and the molar mass is 342g/mol. So put these in the formula: number of moles = 100.8g / 342 g/mol gives approximately 0.294 moles of Al₂(SO₄)₃.

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