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Answer :
The specific heat capacity of the metal object is b. 126 J/(kg·°C).
To determine the specific heat capacity (c), we use the formula:
Q = mcΔT
where Q is the heat added (5020 J), m is the mass (2.00 kg), and ΔT is the change in temperature (40.0°C - 20.0°C = 20.0°C).
Rearranging the formula to solve for c:
c = Q / (mΔT)
Substitute the known values into the equation:
c = 5020 J / (2.00 kg * 20.0°C)
c = 5020 J / 40(kg·°C)
c = 125.5 J/(kg·°C)
c = 126 J/(kg·°C)
Therefore, the specific heat capacity of the metal is 126 J/(kg·°C).
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