We appreciate your visit to A strongman drags a 122 kg tire across the ground with an acceleration of tex 1 20 text m s 2 tex If there is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The strongman must pull with a force of 666.4 newtons to drag the 122kg tire across the ground at an acceleration of 1.20m/s^2, considering there is 520N of friction to overcome.
Explanation:
To calculate the force the strongman pulls with, we apply Newton's second law, which states that the force is the product of mass and acceleration (F = m × a). Given the mass (m) of the tire is 122kg and the acceleration (a) is 1.20m/s2, the force due to acceleration can be calculated as:
F = 122kg × 1.20m/s2 = 146.4N (force due to acceleration).
However, we must also overcome the force of friction, which is given as 520N. The total force the strongman needs to apply is the sum of the force due to acceleration and the frictional force:
Total force = Force due to acceleration + Frictional force
Total force = 146.4N + 520N = 666.4N.
Thus, the strongman must pull with a force of 666.4 newtons to drag the tire across the ground at the given acceleration of 1.20m/s2, overcoming the friction.
Thanks for taking the time to read A strongman drags a 122 kg tire across the ground with an acceleration of tex 1 20 text m s 2 tex If there is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
