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Answer :
Final answer:
This response addresses finding the vapour pressures in a solution through the concepts of Raoult's law and Dalton's law. The mole fractions play a crucial role in arriving at these values. The exact numerical results depend on the specific values provided in the problem.
Explanation:
Part A: To find the vapour pressure of water in the given solution, you will need to use Raoult's law. The vapour pressure of the solvent over the solution, PH2O, is given by the product of the mole fraction of water (XH2O) and the vapour pressure of pure water (PH2Oo). The mole fraction of water is given by the ratio of moles of water to total moles in the solution.
Part B: The total vapour pressure (Ptotal) over the solution is given by the sum of the products of the mole fractions and the vapour pressures of each component (i.e., Ptotal= [Xcy x Pcyo] + [Xac x Paco]). You can find the mole fractions by taking the moles of each component divided by the total moles in the solution.
Part C: The mole fraction of cyclohexane in the vapor phase (Xcy(vapour)) can be computed using Dalton's law of partial pressures. This is equal to the partial pressure of cyclohexane divided by the total vapour pressure. The partial pressure of cyclohexane can be found similar to Part B.
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