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What is the molarity of a solution formed by dissolving 97.7 g of LiBr in enough water to yield 1500.0 mL of solution?

(Note: The correct answer is 0.750 M, but please show the steps to arrive at this solution.)

Answer :

The molarity of the solution formed by dissolving 97.7 g of LiBr in enough water to yield 1500.0 mL of solution is 0.750 M.

To calculate the molarity of a solution, we need to determine the number of moles of the solute (LiBr) and the volume of the solution in liters.

Step 1: Calculate the number of moles of LiBr.

Given mass of LiBr = 97.7 g

Molar mass of LiBr = 7.0 g/mol (Li) + 79.9 g/mol (Br) = 86.9 g/mol

Number of moles of LiBr = Mass / Molar mass = 97.7 g / 86.9 g/mol = 1.125 mol

Step 2: Convert the volume of the solution to liters.

Given volume of solution = 1500.0 mL = 1500.0 mL / 1000 mL/L = 1.500 L

Step 3: Calculate the molarity.

Molarity = Number of moles / Volume of solution = 1.125 mol / 1.500 L = 0.750 M

Therefore, the molarity of the LiBr solution is 0.750 M.

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