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About 4% of the population has a particular genetic mutation.

If 173 people are randomly selected, find the mean number of people with the genetic mutation in such groups of 173.

Answer :

Final answer:

Given that about 4% of the population has a particular genetic mutation, to find the mean number of people with this mutation in groups of 173, we employ the binomial distribution mean formula: μ = n*p. Here, n=173 and p=0.04. The output is 6.92, which we can round up to 7 as we can't have a fraction of an individual.

Explanation:

The student's question asks us to find the mean for the number of people with a particular genetic mutation in groups of 173 randomly selected individuals, given that about 4% of the population has this mutation.

This is a problem related to the concept of probability distribution, specifically, the binomial distribution which describes the number of successes in a fixed number of independent Bernoulli trials with the same probability of success.

The mean of a binomial distribution can be found using the formula: μ = n*p, where n is the number of trials and p is the probability of success on each trial.

Here, n = 173 (the number of individuals randomly selected) and p = 0.04 (the probability of having the genetic mutation, given that 4% of the population has it).

So, the mean μ = n*p = 173*0.04 = 6.92.

So, on average, we can expect about 7 (since we can't have a fraction of an individual) people with the genetic mutation in such groups of 173 randomly selected individuals.

Learn more about Binomial Distribution here:

https://brainly.com/question/39749902

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