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An aqueous solution of potassium bromide (KBr) has a concentration of 4.60 mol/L and a density of 1.37 g/mL. What are the mass percent and mole fraction of KBr in this solution?

Answer :

Mass percentage of potassium bromide KBr is 40.0% and the mole fraction of potassium bromide KBr is 0.0915.

The ratio of the mass of the solute contained in a solution to the mass of the solution as a whole is known as the mass percent. When the mass of the solute and the volume of the solution are supplied, the mass/volume percent is employed to indicate the Mole fraction concentration of the solution. Mole fraction is the ratio of the moles of one component to the total moles that represent all the components in a solution or other combination.

Brief explanation of solution :-

Molarity of KBr solution = 4.60 mol/L

Density of solution d= 1.37 g/mL

Molar mass of KBr=119.002 g/mol

a) Mass percentage of KBr ,(%):

We have formula that M = mxdx10/MW

Here, m is mass of KBr and MW is molar mass of KBr.

M is molarity of solution

Then, m= MXMW/dx10

= 4.60×119.002 /1.37×10

=39.95 or 40.0

mass percentage of KBr is 40.0%.

b) Mole fraction of KBr in solution:

Weight of solution, w = dxV

=1.37g/mL *1000mL

=1370g

So, mass of water, [tex]W_{H2O}[/tex] = 1370-(4.60x119.002)

=1370-547.409

= 822.59g

No. of moles of water = mass of water / MW. of water

= 822.59g/18.02 g/mol

=45.65mol

Now, the mole fraction of KBr (solute) is

квт = No. of moles of KBr / Total no. of moles in solution

= 4.60 mol (4.60+45.65)mol =0.0915

Mole fraction of KBr= 0.0915

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