High School

We appreciate your visit to The value of the electric field at a distance of 38 6 m from a point charge is 67 7 N C and is directed. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

The value of the electric field at a distance of 38.6 m from a point charge is 67.7 N/C and is directed radially in toward the charge. What is the charge? The Coulomb constant is 8.98755×10 9

N⋅m 2

/C 2

. Answer in units of C.

Answer :

To determine the charge of the point charge, we can use the formula for the electric field generated by a point charge:
Electric Field (E) = (k * q) / r^2,
where E is the electric field, k is the Coulomb constant (8.98755 × 10^9 N·m^2/C^2), q is the charge, and r is the distance from the point charge.

In this case, we have an electric field of 67.7 N/C at a distance of 38.6 m. Substituting these values into the formula, we can solve for q:
67.7 N/C = (8.98755 × 10^9 N·m^2/C^2 * q) / (38.6 m)^2.
Simplifying the equation, we find:
q = (67.7 N/C * (38.6 m)^2) / (8.98755 × 10^9 N·m^2/C^2).
Evaluating this expression, we can find the value of q in coulombs.

To learn more about electric click on:brainly.com/question/12990974

#SPJ11

Thanks for taking the time to read The value of the electric field at a distance of 38 6 m from a point charge is 67 7 N C and is directed. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada