High School

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Karissa begins to solve the equation [tex]\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)[/tex]. Her work is correct and is shown below.

[tex]
\begin{array}{c}
\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4) \\
\frac{1}{2} x-7+11=\frac{1}{2} x-x+4 \\
\frac{1}{2} x+4=-\frac{1}{2} x+4
\end{array}
[/tex]

When she subtracts 4 from both sides, [tex]\frac{1}{2} x=-\frac{1}{2} x[/tex] results. What is the value of [tex]x[/tex]?

A. -1
B. [tex]-\frac{1}{2}[/tex]
C. 0
D. [tex]\frac{1}{2}[/tex]

Answer :

We start with the equation

[tex]$$
\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4).
$$[/tex]

First, we simplify both sides by applying the distributive property:

1. On the left-hand side, distribute [tex]$\frac{1}{2}$[/tex] over [tex]$(x-14)$[/tex]:
[tex]$$
\frac{1}{2}(x-14) = \frac{1}{2}x - 7.
$$[/tex]
Then add 11:
[tex]$$
\frac{1}{2}x - 7 + 11 = \frac{1}{2}x + 4.
$$[/tex]

2. On the right-hand side, distribute the negative over [tex]$(x-4)$[/tex]:
[tex]$$
\frac{1}{2}x - (x-4) = \frac{1}{2}x - x + 4.
$$[/tex]
Notice that
[tex]$$
\frac{1}{2}x - x = -\frac{1}{2}x,
$$[/tex]
so the right-hand side becomes:
[tex]$$
-\frac{1}{2}x + 4.
$$[/tex]

The simplified equation is now

[tex]$$
\frac{1}{2}x + 4 = -\frac{1}{2}x + 4.
$$[/tex]

Next, subtract 4 from both sides to remove the constant term:

[tex]$$
\frac{1}{2}x + 4 - 4 = -\frac{1}{2}x + 4 - 4,
$$[/tex]

which simplifies to

[tex]$$
\frac{1}{2}x = -\frac{1}{2}x.
$$[/tex]

To solve for [tex]$x$[/tex], add [tex]$\frac{1}{2}x$[/tex] to both sides:

[tex]$$
\frac{1}{2}x + \frac{1}{2}x = 0,
$$[/tex]

which gives

[tex]$$
x = 0.
$$[/tex]

Thus, the value of [tex]$x$[/tex] is [tex]$\boxed{0}$[/tex].

Thanks for taking the time to read Karissa begins to solve the equation tex frac 1 2 x 14 11 frac 1 2 x x 4 tex Her work is correct and. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

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