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Answer :
Final answer:
The velocity of the 137 kg player just before the tackle is approximately 1.90 m/s.
Explanation:
To find the velocity of the 137 kg player just before the tackle, we can use the principle of conservation of momentum. In an inelastic collision, the total momentum before the collision is equal to the total momentum after the collision. The momentum, which is the product of mass and velocity, is given by the formula:
momentum = mass × velocity
Let's assume the initial velocity of the 137 kg player is v, then the momentum before the collision is 137 kg × v kg/s.
After the tackle, the two players move together at a velocity of 1.8 m/s north. Since the mass of the opponent is 123 kg, the total momentum after the collision is (137 kg + 123 kg) × 1.8 m/s.
According to the conservation of momentum, the momentum before the collision is equal to the momentum after the collision:
137 kg × v kg/s = (137 kg + 123 kg) × 1.8 m/s
Simplifying the equation:
137v = 260.4
Dividing both sides by 137, we get:
v ≈ 1.90 m/s
Therefore, the velocity of the 137 kg player just before the tackle is approximately 1.90 m/s.
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