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Answer :
Final answer:
The approximate heat capacity of a calorimeter containing 99.3 g of water is approximately 414.174 J/°C.
Explanation:
To calculate the approximate heat capacity of a calorimeter containing 99.3 g of water, we need to consider the specific heat capacity of water and the mass of water in the calorimeter.
The specific heat capacity of water is approximately 4.18 J/g°C. This means that it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
Given that we have 99.3 g of water in the calorimeter, we can calculate the approximate heat capacity as follows:
- Heat capacity = mass of water * specific heat capacity of water
- Heat capacity = 99.3 g * 4.18 J/g°C
- Heat capacity ≈ 414.174 J/°C
Therefore, the approximate heat capacity of the calorimeter containing 99.3 g of water is approximately 414.174 J/°C.
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