High School

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A sample of 95 body temperatures has a mean of 98.2. Assume the standard deviation is known to be 0.5 ºF. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.5 ºF, as is commonly believed.

What is the value of the test statistic for this test? (Round the answer to two decimal places.)

Answer :

The test statistic for this problem is given as follows:

z = -5.85.

How to obtain the test statistic?

The equation for the test statistic is given as follows:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which:

  • [tex]\overline{x}[/tex] is the sample mean.
  • [tex]\mu[/tex] is the value tested at the null hypothesis.
  • [tex]\sigma[/tex] is the standard deviation of the population.
  • n is the sample size.

The parameters for this problem are given as follows:

[tex]\overline{x} = 98.2, \mu = 98.5, \sigma = 0.5, n = 95[/tex]

Hence the test statistic is given as follows:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{98.2 - 98.5}{\frac{0.5}{\sqrt{95}}}[/tex]

z = -5.85.

More can be learned about the z-distribution at https://brainly.com/question/25890103

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