High School

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What is the remainder when [tex]3x^3 – 2x^2 + 4x – 3[/tex] is divided by [tex]x^2 + 3x + 3[/tex]?

A. 30
B. 3x – 11
C. 28x – 36
D. 28x + 30

Answer :

The answer would be 28x+30.


You can do this by doing long division.

Refer to the attachment please.


The final quotient will then be 3x - 11 remainder 28x + 30

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Rewritten by : Barada

Answer:

Option D is correct.

Step-by-step explanation:

Given:

Dividend = 3x³ - 2x² + 4x - 3

Divisor = x² + 3x + 3

To find: Remainder

We use Long Division Method (Synthetic Division Method)

Step 1 : we find first factor which we get 3x as 3x × x² = 3x³ the first term of dividend. Now, we multiply it with divisor and subtract from dividend.

Step 2: after subtraction we get -11x² - 5x - 3 as new dividend

Step 3 : Now we find 2nd factor which is -11 as -11 × x² = -11x². Now, we multiply it with divisor and subtract from new dividend

Step 4: After step 3 we get 28x + 30 , which is our required remainder

Therefore, Option D is correct .i.e., Remainder is 28x + 30