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Answer :
The original kinetic energy of the football player is [tex]\( 42 \, \text{J} \).[/tex]
To find the original kinetic energy of the football player, we can use the formula for kinetic energy:
[tex]\[ KE = \frac{1}{2} m v^2 \][/tex]
Where:
-[tex]\( KE[/tex] is the kinetic energy,
[tex]- \( m \)[/tex] is the mass of the football player (84 kg),
-[tex]\( v \)[/tex] is the initial velocity of the football player (2.8 m/s).
Plugging in the given values:
[tex]\[ KE = \frac{1}{2} \times 84 \, \text{kg} \times (2.8 \, \text{m/s})^2 \][/tex]
[tex]\[ KE = \frac{1}{2} \times 84 \, \text{kg} \times 7.84 \, \text{m}^2/\text{s}^2 \][/tex]
[tex]\[ KE = 42 \, \text{kg} \times \text{m}^2/\text{s}^2 \][/tex]
[tex]\[ KE = 42 \, \text{J} \][/tex]
So, the original kinetic energy of the football player is [tex]\( 42 \, \text{J} \).[/tex]
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