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Answer :
To find the percentage of people aged 20 to 34 with IQs between 125 and 150, when the IQ scores are normally distributed with a mean ([tex]\mu[/tex]) of 110 and a standard deviation ([tex]\sigma[/tex]) of 25, we will use the properties of the normal distribution.
Step 1: Standardize the Scores
We will convert the IQ scores to z-scores using the formula:
[tex]z = \frac{X - \mu}{\sigma}[/tex]
For an IQ of 125:
[tex]z = \frac{125 - 110}{25} = \frac{15}{25} = 0.6[/tex]For an IQ of 150:
[tex]z = \frac{150 - 110}{25} = \frac{40}{25} = 1.6[/tex]
Step 2: Find the Corresponding Percentages
Using a standard normal distribution table (z-table), or a calculator with normal distribution functions, we find the area (or probability) that corresponds to these z-scores:
The probability (or area) for [tex]z = 0.6[/tex] is approximately [tex]0.7257[/tex].
The probability (or area) for [tex]z = 1.6[/tex] is approximately [tex]0.9452[/tex].
Step 3: Calculate the Percentage
To find the percentage of people who have IQs between 125 and 150, we subtract the smaller area from the larger area:
[tex]0.9452 - 0.7257 = 0.2195[/tex]
This means approximately [tex]21.95\%[/tex] of people aged 20 to 34 have IQs between 125 and 150.
Therefore, according to our calculations based on a normally distributed data assumption, about [tex]21.95\%[/tex] of individuals in this age group would have IQ scores in the specified range.
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