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Answer :
The molarity of the H2SO4 solution is approximately 0.12453 M.To calculate the molarity of the H2SO4 solution, we can use the concept of stoichiometry. The balanced chemical equation for the neutralization reaction between KOH and H2SO4 is:
2 KOH + H2SO4 -> K2SO4 + 2 H2O
From the equation, we can see that 2 moles of KOH react with 1 mole of H2SO4.
First, we need to calculate the number of moles of KOH used. We can use the formula:
moles = volume (in liters) * molarity
Given that the volume of KOH used is 38.2 ml (or 0.0382 L) and the molarity of KOH is 0.163 M, we can calculate the moles of KOH used:
moles of KOH = 0.0382 L * 0.163 M = 0.0062266 moles of KOH
Since the mole ratio between KOH and H2SO4 is 2:1, the moles of H2SO4 used will be half of the moles of KOH used:
moles of H2SO4 = 0.0062266 moles of KOH / 2 = 0.0031133 moles of H2SO4
Next, we need to calculate the molarity of H2SO4. The formula for molarity is:
molarity = moles / volume (in liters)
Given that the volume of H2SO4 used is 25.0 ml (or 0.025 L), we can calculate the molarity of H2SO4:
molarity of H2SO4 = 0.0031133 moles of H2SO4 / 0.025 L = 0.12453 M
Therefore, the molarity of the H2SO4 solution is approximately 0.12453 M.
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The molarity of the H2SO4 solution is approximately 0.2491 M.
To calculate the molarity of the H2SO4 solution, we can use the equation:
M1V1 = M2V2
where M1 is the molarity of KOH solution, V1 is the volume of KOH solution, M2 is the molarity of H2SO4 solution, and V2 is the volume of H2SO4 solution.
Given:
M1 = 0.163 M (molarity of KOH solution)
V1 = 38.2 mL (volume of KOH solution)
V2 = 25.0 mL (volume of H2SO4 solution)
Now we can substitute the given values into the equation:
(0.163 M)(38.2 mL) = M2(25.0 mL)
Simplifying the equation:
6.2266 = 25.0 M2
Dividing both sides by 25.0:
M2 = 6.2266 / 25.0
M2 = 0.2491 M
Therefore, the molarity of the H2SO4 solution is approximately 0.2491 M.
In summary, to find the molarity of the H2SO4 solution, we used the equation M1V1 = M2V2, substituted the given values, and solved for M2. The molarity of the H2SO4 solution is approximately 0.2491 M.
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