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A rock is thrown upward with an initial velocity of 29 m/s. What is the rock's maximum height?

A. 43 m
B. 35.8 m
C. 14.5 m
D. 58 m

Answer :

V^2 = u ^2 + 2 a S
0 = 29^2 - 2 x 9.8 x s
19.6 s = 841

s = 841/19.6 = 42.9 m

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