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A rectangular site measures 125 feet (frontage) by 256 feet (depth), of which 26 feet is in the public right of way. What is the gross and net site area?

A. 0.66 acre gross and 0.73 acre net
B. 35,100 square feet gross area and 32,000 square feet net area
C. 38,656 square feet gross area and 32,000 square feet net area
D. 32,000 square feet gross area and 28,750 square feet net area

Answer :

Answer:

32,000 square feet gross area and 28,750 square feet net area

Step-by-step explanation:

Given a rectangular site measures 125 feet (frontage) by 256 feet (depth), of which 26 feet is in the public right of way. We have to find the the gross and net site area.

As, 26 feet width is in the public right of way which excluded in the net area but included in gross area.

For gross area,

Length=125 feet

Width=256 feet

[tex]Area=Length\times width=125\times 256=32000 square feet[/tex]

For net area,

Length=125 feet

Width=256-26=230 feet

[tex]Area=Length\times width=125\times 230=28750 square feet[/tex]

Hence, last option is correct.

The answer is: 32,000 square feet gross area and 28,750 square feet net area

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Rewritten by : Barada

The correct answer is 32,000 square feet gross area and 28,750 square feet net area.

To find the gross and net site areas, we need to perform some calculations.

Gross area: We start with the gross measurements of the rectangular site.

The frontage (width) is 125 feet.The depth (length) is 256 feet.

Gross area = 125 feet × 256 feet = 32,000 square feet.

Net area: The public right of way takes up 26 feet of the depth, so we subtract this from the original depth.

Net depth = 256 feet - 26 feet = 230 feet.

The net area is then calculated as:

Net area = 125 feet × 230 feet = 28,750 square feet.

Therefore, the correct answer is 32,000 square feet gross area and 28,750 square feet net area.