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Answer :
The change in entropy for the vaporization of ethanol is approximately 109.8 J/mol·K.
To calculate the change in entropy (ΔS) for the vaporization of ethanol, we will use the formula:
ΔS = ΔHvap / T Where ΔHvap is the enthalpy of vaporization, and T is the temperature in Kelvin.
Given:
ΔHvap = 38.6 kJ/mol
Boiling point = 78.3 °C
First, convert the boiling point to Kelvin:
T = 78.3 + 273.15 = 351.45 K
Now, plug the values into the formula:
ΔS = (38.6 kJ/mol) / (351.45 K)
Since 1 kJ is equal to 1000 J, we need to convert kJ to J:
ΔS = (38.6 * 1000 J/mol) / (351.45 K)
ΔS = 38600 J/mol / 351.45 K
ΔS ≈ 109.8 J/mol·K
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