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What reflux ratio was used in a C2 splitter to obtain a 99.9 mol percent ethylene product using a 4.63-m-diameter column provided with 94 sieve trays? Assume that the distillate is 99.9 mol% ethylene.

Answer :

The reflux ratio was used in a C2 splitter to obtain a 99.9 mol percent ethylene product using a 4.63-m-diameter column provided with 94 sieve trays is 0.9895.

The reflux ratio refers to the ratio of the liquid reflux (returned liquid) to the overhead distillate in a distillation column. In order to obtain a 99.9 mol percent ethylene product in a C2 splitter, the reflux ratio needs to be determined.

To calculate the reflux ratio, we need to consider the mole fraction of ethylene in the distillate and the number of trays in the column. In this case, the distillate is given to be 99.9 mol percent ethylene. This means that in every 100 moles of distillate, 99.9 moles are ethylene. Since the distillate is pure ethylene, the mole fraction of ethylene in the distillate is 1. The number of trays in the column is given as 94.

To calculate the reflux ratio, we can use the equation:

Reflux Ratio = Number of Trays / (Number of Trays + 1)

Plugging in the values:

Reflux Ratio = 94 / (94 + 1) = 94 / 95 ≈ 0.9895

Therefore, the reflux ratio used in the C2 splitter to obtain a 99.9 mol percent ethylene product is approximately 0.9895.

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