Answer :

The amount of oxygen reacted can be calculated by subtracting the mass of hydrogen from the mass of water, which gives 351 g - 39.3 g = 311.7 g of oxygen reacted.

In the given reaction, hydrogen reacts with oxygen to produce water. From the provided information, we can infer that the entire mass of hydrogen has reacted to form water. Since the molar ratio between hydrogen and oxygen in the reaction is 2:1, we know that the mass of oxygen reacted will be twice the mass of hydrogen.

The molar mass of hydrogen is approximately 1 g/mol, and the molar mass of oxygen is approximately 16 g/mol. Therefore, the mass of oxygen reacted can be calculated as follows:

Mass of hydrogen = 39.3 g

Mass of oxygen reacted = 2 * Mass of hydrogen = 2 * 39.3 g = 78.6 g

However, the given information states that 351 g of water is produced. The molar mass of water is approximately 18 g/mol. Using the molar mass ratio of oxygen in water (16 g/mol) to the molar mass of water (18 g/mol), we can find the mass of oxygen reacted:

Mass of oxygen reacted = (Mass of water - Mass of hydrogen) = 351 g - 39.3 g = 311.7 g.

Therefore, 311.7 g of oxygen reacted to produce 351 g of water when 39.3 g of hydrogen was burned.

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